SList.opEquals

Comparison for equality.

Complexity: O(min(n, n1)) where n1 is the number of elements in rhs.

  1. bool opEquals(SList rhs)
  2. bool opEquals(SList rhs)
    struct SList(T)
    const
    bool
    opEquals
    (
    ref const SList rhs
    )
    if (
    !is(T == shared)
    )

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