popBackExactly

Eagerly advances r itself (not a copy) exactly n times (by calling r.popFront). popFrontExactly takes r by ref, so it mutates the original range. Completes in O(1) steps for ranges that support slicing, and have either length or are infinite. Completes in O(n) time for all other ranges.

Note: Unlike popFrontN, popFrontExactly will assume that the range holds at least n elements. This makes popFrontExactly faster than popFrontN, but it also means that if range does not contain at least n elements, it will attempt to call popFront on an empty range, which is undefined behavior. So, only use popFrontExactly when it is guaranteed that range holds at least n elements.

popBackExactly will behave the same but instead removes elements from the back of the (bidirectional) range instead of the front.

Examples

import std.algorithm.comparison : equal;
import std.algorithm.iteration : filterBidirectional;

auto a = [1, 2, 3];
a.popFrontExactly(1);
assert(a == [2, 3]);
a.popBackExactly(1);
assert(a == [2]);

string s = "日本語";
s.popFrontExactly(1);
assert(s == "本語");
s.popBackExactly(1);
assert(s == "本");

auto bd = filterBidirectional!"true"([1, 2, 3]);
bd.popFrontExactly(1);
assert(bd.equal([2, 3]));
bd.popBackExactly(1);
assert(bd.equal([2]));

See Also

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